14312112000 has 128 divisors (see below), whose sum is σ = 47444810400. Its totient is φ = 3816550400.

The previous prime is 14312111999. The next prime is 14312112019. The reversal of 14312112000 is 21121341.

It is a tau number, because it is divible by the number of its divisors (128).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101085 + ... + 197084.

Almost surely, 2^14312112000 is an apocalyptic number.

14312112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14312112000 is an abundant number, since it is smaller than the sum of its proper divisors (33132698400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14312112000 is an equidigital number, since it uses as much as digits as its factorization.

14312112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298201 (or 298179 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 14312112000 its reverse (21121341), we get a palindrome (14333233341).

The spelling of 14312112000 in words is "fourteen billion, three hundred twelve million, one hundred twelve thousand".