143122221341 has 4 divisors (see below), whose sum is σ = 156133332384. Its totient is φ = 130111110300.

The previous prime is 143122221323. The next prime is 143122221467.

It is a happy number.

143122221341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143122221341 - 2¹⁰ = 143122220317 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 143122221341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143122221311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6505555505 + ... + 6505555526.

It is an arithmetic number, because the mean of its divisors is an integer number (39033333096).

Almost surely, 2^143122221341 is an apocalyptic number.

143122221341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143122221341 is a deficient number, since it is larger than the sum of its proper divisors (13011111043).

143122221341 is a wasteful number, since it uses less digits than its factorization.

143122221341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13011111042.

The product of its digits is 2304, while the sum is 26.

It can be divided in two parts, 143122 and 221341, that added together give a palindrome (364463).

The spelling of 143122221341 in words is "one hundred forty-three billion, one hundred twenty-two million, two hundred twenty-one thousand, three hundred forty-one".