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14312230115 = 513121850733
BaseRepresentation
bin11010101010001001…
…10100110011100011
31100221102222121202212
431111010310303203
5213302412330430
610324104432335
71014445643261
oct152504646343
940842877685
1014312230115
116084976357
1229351786ab
1314711cc621
1499ab51431
1558b75ab95
hex355134ce3

14312230115 has 8 divisors (see below), whose sum is σ = 17305781328. Its totient is φ = 11362380640.

The previous prime is 14312230099. The next prime is 14312230139. The reversal of 14312230115 is 51103221341.

14312230115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14312230115 - 24 = 14312230099 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10924712 + ... + 10926021.

It is an arithmetic number, because the mean of its divisors is an integer number (2163222666).

Almost surely, 214312230115 is an apocalyptic number.

14312230115 is a deficient number, since it is larger than the sum of its proper divisors (2993551213).

14312230115 is a wasteful number, since it uses less digits than its factorization.

14312230115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21850869.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 14312230115 its reverse (51103221341), we get a palindrome (65415451456).

The spelling of 14312230115 in words is "fourteen billion, three hundred twelve million, two hundred thirty thousand, one hundred fifteen".

Divisors: 1 5 131 655 21850733 109253665 2862446023 14312230115