Base | Representation |
---|---|
bin | 11010101010001001… |
… | …10101110001111111 |
3 | 1100221102222211020212 |
4 | 31111010311301333 |
5 | 213302412442421 |
6 | 10324104503035 |
7 | 1014445661030 |
oct | 152504656177 |
9 | 40842884225 |
10 | 14312234111 |
11 | 608497935a |
12 | 293517aa7b |
13 | 14712013a6 |
14 | 99ab52a87 |
15 | 58b75be5b |
hex | 355135c7f |
14312234111 has 4 divisors (see below), whose sum is σ = 16356838992. Its totient is φ = 12267629232.
The previous prime is 14312234059. The next prime is 14312234113. The reversal of 14312234111 is 11143221341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11143221341 = 7 ⋅1591888763.
It is a cyclic number.
It is not a de Polignac number, because 14312234111 - 26 = 14312234047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14312234113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1022302430 + ... + 1022302443.
It is an arithmetic number, because the mean of its divisors is an integer number (4089209748).
Almost surely, 214312234111 is an apocalyptic number.
14312234111 is a deficient number, since it is larger than the sum of its proper divisors (2044604881).
14312234111 is an equidigital number, since it uses as much as digits as its factorization.
14312234111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2044604880.
The product of its digits is 576, while the sum is 23.
Adding to 14312234111 its reverse (11143221341), we get a palindrome (25455455452).
The spelling of 14312234111 in words is "fourteen billion, three hundred twelve million, two hundred thirty-four thousand, one hundred eleven".
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