Search a number
-
+
1431224221341 = 3477074740447
BaseRepresentation
bin10100110100111011100…
…111000111111010011101
312001211020110212120211010
4110310323213013322131
5141422121400040331
63013254554045433
7205255033104225
oct24647347077235
95054213776733
101431224221341
11501a848409a2
121b146a119879
13a4c6b7c40a5
144d3b348b085
15273694aae46
hex14d3b9c7e9d

1431224221341 has 4 divisors (see below), whose sum is σ = 1908298961792. Its totient is φ = 954149480892.

The previous prime is 1431224221327. The next prime is 1431224221367.

It is a happy number.

1431224221341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-1431224221341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431224221299 and 1431224221308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431224221321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238537370221 + ... + 238537370226.

It is an arithmetic number, because the mean of its divisors is an integer number (477074740448).

Almost surely, 21431224221341 is an apocalyptic number.

It is an amenable number.

1431224221341 is a deficient number, since it is larger than the sum of its proper divisors (477074740451).

1431224221341 is an equidigital number, since it uses as much as digits as its factorization.

1431224221341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 477074740450.

The product of its digits is 9216, while the sum is 30.

The spelling of 1431224221341 in words is "one trillion, four hundred thirty-one billion, two hundred twenty-four million, two hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 3 477074740447 1431224221341