143124011 has 2 divisors, whose sum is σ = 143124012. Its totient is φ = 143124010.

The previous prime is 143123999. The next prime is 143124013. The reversal of 143124011 is 110421341.

It is a happy number.

143124011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143124011 is a prime.

Together with 143124013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143124013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562005 + 71562006.

It is an arithmetic number, because the mean of its divisors is an integer number (71562006).

Almost surely, 2^143124011 is an apocalyptic number.

143124011 is a deficient number, since it is larger than the sum of its proper divisors (1).

143124011 is an equidigital number, since it uses as much as digits as its factorization.

143124011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 143124011 is about 11963.4447798283. Note that the first 3 decimals coincide. The cubic root of 143124011 is about 523.0832734606.

Adding to 143124011 its reverse (110421341), we get a palindrome (253545352).

The spelling of 143124011 in words is "one hundred forty-three million, one hundred twenty-four thousand, eleven".