Base | Representation |
---|---|
bin | 101010101001111… |
… | …0010110001010111 |
3 | 10200202011010201101 |
4 | 1111103302301113 |
5 | 10412400031210 |
6 | 354004410531 |
7 | 50316304342 |
oct | 12523626127 |
9 | 3622133641 |
10 | 1431252055 |
11 | 6749a4942 |
12 | 33b3a6a47 |
13 | 19a6a160c |
14 | d8129459 |
15 | 859b9a3a |
hex | 554f2c57 |
1431252055 has 4 divisors (see below), whose sum is σ = 1717502472. Its totient is φ = 1145001640.
The previous prime is 1431252047. The next prime is 1431252059. The reversal of 1431252055 is 5502521341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5502521341 = 37 ⋅148716793.
It is not a de Polignac number, because 1431252055 - 23 = 1431252047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1431252059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143125201 + ... + 143125210.
It is an arithmetic number, because the mean of its divisors is an integer number (429375618).
Almost surely, 21431252055 is an apocalyptic number.
1431252055 is a deficient number, since it is larger than the sum of its proper divisors (286250417).
1431252055 is an equidigital number, since it uses as much as digits as its factorization.
1431252055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 286250416.
The product of its (nonzero) digits is 6000, while the sum is 28.
The square root of 1431252055 is about 37831.8920356886. The cubic root of 1431252055 is about 1126.9518852476.
Adding to 1431252055 its reverse (5502521341), we get a palindrome (6933773396).
The spelling of 1431252055 in words is "one billion, four hundred thirty-one million, two hundred fifty-two thousand, fifty-five".
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