Base | Representation |
---|---|
bin | 1000010101001011110… |
… | …0000100001001111111 |
3 | 111200102122200112222222 |
4 | 2011102330010021333 |
5 | 4321110100220033 |
6 | 145430105555555 |
7 | 13224531545150 |
oct | 2052274041177 |
9 | 450378615888 |
10 | 143125398143 |
11 | 55776613012 |
12 | 238a44a5bbb |
13 | 1065c240500 |
14 | 6cda757927 |
15 | 3aca2d5598 |
hex | 2152f0427f |
143125398143 has 24 divisors (see below), whose sum is σ = 177154499808. Its totient is φ = 113221435392.
The previous prime is 143125398107. The next prime is 143125398151. The reversal of 143125398143 is 341893521341.
It is a happy number.
It is not a de Polignac number, because 143125398143 - 212 = 143125394047 is a prime.
It is a super-3 number, since 3×1431253981433 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 143125398094 and 143125398103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143125398103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12147071 + ... + 12158847.
It is an arithmetic number, because the mean of its divisors is an integer number (7381437492).
Almost surely, 2143125398143 is an apocalyptic number.
143125398143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
143125398143 is a deficient number, since it is larger than the sum of its proper divisors (34029101665).
143125398143 is a wasteful number, since it uses less digits than its factorization.
143125398143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22083 (or 22070 counting only the distinct ones).
The product of its digits is 311040, while the sum is 44.
The spelling of 143125398143 in words is "one hundred forty-three billion, one hundred twenty-five million, three hundred ninety-eight thousand, one hundred forty-three".
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