143132231341 has 4 divisors (see below), whose sum is σ = 156144252384. Its totient is φ = 130120210300.

The previous prime is 143132231329. The next prime is 143132231369.

143132231341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143132231341 - 2⁵ = 143132231309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143132231311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6506010505 + ... + 6506010526.

It is an arithmetic number, because the mean of its divisors is an integer number (39036063096).

Almost surely, 2^143132231341 is an apocalyptic number.

143132231341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143132231341 is a deficient number, since it is larger than the sum of its proper divisors (13012021043).

143132231341 is a wasteful number, since it uses less digits than its factorization.

143132231341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13012021042.

The product of its digits is 5184, while the sum is 28.

It can be divided in two parts, 143132 and 231341, that added together give a palindrome (374473).

The spelling of 143132231341 in words is "one hundred forty-three billion, one hundred thirty-two million, two hundred thirty-one thousand, three hundred forty-one".