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143134546363103 is a prime number
BaseRepresentation
bin100000100010111000011011…
…110010101000001011011111
3200202210112021122020020101202
4200202320123302220023133
5122230104022332104403
61224231034114030115
742102062330540351
oct4042703362501337
9622715248206352
10143134546363103
1141675024a03a29
1214078525b7833b
1361b36b6ca27b9
14274ba6b3c70d1
1511833d0c8e688
hex822e1bca82df

143134546363103 has 2 divisors, whose sum is σ = 143134546363104. Its totient is φ = 143134546363102.

The previous prime is 143134546363031. The next prime is 143134546363163. The reversal of 143134546363103 is 301363645431341.

It is a happy number.

Together with previous prime (143134546363031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143134546363103 - 222 = 143134542168799 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143134546363163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71567273181551 + 71567273181552.

It is an arithmetic number, because the mean of its divisors is an integer number (71567273181552).

Almost surely, 2143134546363103 is an apocalyptic number.

143134546363103 is a deficient number, since it is larger than the sum of its proper divisors (1).

143134546363103 is an equidigital number, since it uses as much as digits as its factorization.

143134546363103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2799360, while the sum is 47.

The spelling of 143134546363103 in words is "one hundred forty-three trillion, one hundred thirty-four billion, five hundred forty-six million, three hundred sixty-three thousand, one hundred three".