1431362631341 has 4 divisors (see below), whose sum is σ = 1445534538684. Its totient is φ = 1417190724000.

The previous prime is 1431362631329. The next prime is 1431362631343.

1431362631341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1405386540100 + 25976091241 = 1185490^2 + 161171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1431362631341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431362631295 and 1431362631304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431362631343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7085953520 + ... + 7085953721.

It is an arithmetic number, because the mean of its divisors is an integer number (361383634671).

Almost surely, 2^{1431362631341} is an apocalyptic number.

It is an amenable number.

1431362631341 is a deficient number, since it is larger than the sum of its proper divisors (14171907343).

1431362631341 is a wasteful number, since it uses less digits than its factorization.

1431362631341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14171907342.

The product of its digits is 93312, while the sum is 38.

The spelling of 1431362631341 in words is "one trillion, four hundred thirty-one billion, three hundred sixty-two million, six hundred thirty-one thousand, three hundred forty-one".