Base | Representation |
---|---|
bin | 10100110101000111111… |
… | …100110001000010011111 |
3 | 12001211202220101021112020 |
4 | 110311013330301002133 |
5 | 141423032343041112 |
6 | 3013331310511223 |
7 | 205263125425035 |
oct | 24650774610237 |
9 | 5054686337466 |
10 | 1431431221407 |
11 | 502080675130 |
12 | 1b1507505513 |
13 | a4ca265c635 |
14 | 4d3d2b72555 |
15 | 2737c74948c |
hex | 14d47f3109f |
1431431221407 has 16 divisors (see below), whose sum is σ = 2084445135360. Its totient is φ = 866549340800.
The previous prime is 1431431221361. The next prime is 1431431221453. The reversal of 1431431221407 is 7041221341341.
It is an interprime number because it is at equal distance from previous prime (1431431221361) and next prime (1431431221453).
It is not a de Polignac number, because 1431431221407 - 214 = 1431431205023 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1431431221807) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24588807 + ... + 24646952.
It is an arithmetic number, because the mean of its divisors is an integer number (130277820960).
Almost surely, 21431431221407 is an apocalyptic number.
1431431221407 is a deficient number, since it is larger than the sum of its proper divisors (653013913953).
1431431221407 is a wasteful number, since it uses less digits than its factorization.
1431431221407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49236654.
The product of its (nonzero) digits is 16128, while the sum is 33.
Adding to 1431431221407 its reverse (7041221341341), we get a palindrome (8472652562748).
The spelling of 1431431221407 in words is "one trillion, four hundred thirty-one billion, four hundred thirty-one million, two hundred twenty-one thousand, four hundred seven".
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