143145541341 has 24 divisors (see below), whose sum is σ = 228097097280. Its totient is φ = 85780094400.

The previous prime is 143145541333. The next prime is 143145541361.

143145541341 is a `hidden beast` number, since 1 + 4 + 31 + 45 + 541 + 3 + 41 = 666.

143145541341 is nontrivially palindromic in base 10.

143145541341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 143145541341 - 2³ = 143145541333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143145541296 and 143145541305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143145541361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8114305 + ... + 8131926.

It is an arithmetic number, because the mean of its divisors is an integer number (9504045720).

Almost surely, 2^143145541341 is an apocalyptic number.

143145541341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143145541341 is a deficient number, since it is larger than the sum of its proper divisors (84951555939).

143145541341 is a wasteful number, since it uses less digits than its factorization.

143145541341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16246337 (or 16246334 counting only the distinct ones).

The product of its digits is 57600, while the sum is 36.

It can be divided in two parts, 143145 and 541341, that added together give a palindrome (684486).

The spelling of 143145541341 in words is "one hundred forty-three billion, one hundred forty-five million, five hundred forty-one thousand, three hundred forty-one".