Base | Representation |
---|---|
bin | 1101000001100010111001… |
… | …1100100011100001100101 |
3 | 1212200222221101002120201220 |
4 | 3100120232130203201211 |
5 | 3334110232222433331 |
6 | 50242335324410553 |
7 | 3005412624226215 |
oct | 320305634434145 |
9 | 55628841076656 |
10 | 14320200202341 |
11 | 4621187761990 |
12 | 17334260a6a59 |
13 | 7cb509a858b7 |
14 | 37715c2cc245 |
15 | 19c77bbc2296 |
hex | d062e723865 |
14320200202341 has 64 divisors (see below), whose sum is σ = 21792474316800. Its totient is φ = 8285634086400.
The previous prime is 14320200202309. The next prime is 14320200202351.
It is a happy number.
14320200202341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 14320200202341 - 25 = 14320200202309 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14320200202351) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 39790495 + ... + 40148771.
It is an arithmetic number, because the mean of its divisors is an integer number (340507411200).
Almost surely, 214320200202341 is an apocalyptic number.
14320200202341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14320200202341 is a deficient number, since it is larger than the sum of its proper divisors (7472274114459).
14320200202341 is a wasteful number, since it uses less digits than its factorization.
14320200202341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 358850.
The product of its (nonzero) digits is 2304, while the sum is 24.
It can be divided in two parts, 14320200 and 202341, that added together give a palindrome (14522541).
The spelling of 14320200202341 in words is "fourteen trillion, three hundred twenty billion, two hundred million, two hundred two thousand, three hundred forty-one".
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