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1432141323103 is a prime number
BaseRepresentation
bin10100110101110010010…
…001100101101101011111
312001220121101120011221001
4110311302101211231133
5141431011134314403
63013525554451131
7205316540251261
oct24656221455537
95056541504831
101432141323103
11502405494037
121b1685293aa7
13a50867c795a
144d45d1b9b31
15273bec64c1d
hex14d72465b5f

1432141323103 has 2 divisors, whose sum is σ = 1432141323104. Its totient is φ = 1432141323102.

The previous prime is 1432141323101. The next prime is 1432141323157. The reversal of 1432141323103 is 3013231412341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1432141323103 - 21 = 1432141323101 is a prime.

It is a super-2 number, since 2×14321413231032 (a number of 25 digits) contains 22 as substring.

Together with 1432141323101, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1432141323101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716070661551 + 716070661552.

It is an arithmetic number, because the mean of its divisors is an integer number (716070661552).

Almost surely, 21432141323103 is an apocalyptic number.

1432141323103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1432141323103 is an equidigital number, since it uses as much as digits as its factorization.

1432141323103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1432141323103 its reverse (3013231412341), we get a palindrome (4445372735444).

The spelling of 1432141323103 in words is "one trillion, four hundred thirty-two billion, one hundred forty-one million, three hundred twenty-three thousand, one hundred three".