143222303222341 has 8 divisors (see below), whose sum is σ = 163743548774400. Its totient is φ = 122716286800368.

The previous prime is 143222303222293. The next prime is 143222303222351.

It is a happy number.

143222303222341 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143222303222341 - 2¹⁷ = 143222303091269 is a prime.

It is a super-3 number, since 3×143222303222341³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143222303222297 and 143222303222306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143222303222351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3807262366 + ... + 3807299983.

It is an arithmetic number, because the mean of its divisors is an integer number (20467943596800).

Almost surely, 2^{143222303222341} is an apocalyptic number.

It is an amenable number.

143222303222341 is a deficient number, since it is larger than the sum of its proper divisors (20521245552059).

143222303222341 is an equidigital number, since it uses as much as digits as its factorization.

143222303222341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7614565043.

The product of its (nonzero) digits is 82944, while the sum is 34.

It can be divided in two parts, 14322230 and 3222341, that added together give a palindrome (17544571).

The spelling of 143222303222341 in words is "one hundred forty-three trillion, two hundred twenty-two billion, three hundred three million, two hundred twenty-two thousand, three hundred forty-one".