Base | Representation |
---|---|
bin | 1101000001101101010101… |
… | …0101010111000001101110 |
3 | 1212201021011111121200122112 |
4 | 3100123111111113001232 |
5 | 3334132001012024324 |
6 | 50243521224244022 |
7 | 3005542203114644 |
oct | 320332525270156 |
9 | 55637144550575 |
10 | 14323000111214 |
11 | 4622394187963 |
12 | 1733a87910612 |
13 | 7cb864b80502 |
14 | 3773460cb194 |
15 | 19c8928dec0e |
hex | d06d555706e |
14323000111214 has 4 divisors (see below), whose sum is σ = 21484500166824. Its totient is φ = 7161500055606.
The previous prime is 14323000111193. The next prime is 14323000111313. The reversal of 14323000111214 is 41211100032341.
14323000111214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 14323000111214.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3580750027802 + ... + 3580750027805.
It is an arithmetic number, because the mean of its divisors is an integer number (5371125041706).
Almost surely, 214323000111214 is an apocalyptic number.
14323000111214 is a deficient number, since it is larger than the sum of its proper divisors (7161500055610).
14323000111214 is an equidigital number, since it uses as much as digits as its factorization.
14323000111214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7161500055609.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14323000111214 its reverse (41211100032341), we get a palindrome (55534100143555).
The spelling of 14323000111214 in words is "fourteen trillion, three hundred twenty-three billion, one hundred eleven thousand, two hundred fourteen".
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