1432322034133 has 4 divisors (see below), whose sum is σ = 1432390225248. Its totient is φ = 1432253843020.

The previous prime is 1432322034113. The next prime is 1432322034137. The reversal of 1432322034133 is 3314302232341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1432322034133 - 2²¹ = 1432319936981 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1432322034095 and 1432322034104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1432322034137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34064041 + ... + 34106062.

It is an arithmetic number, because the mean of its divisors is an integer number (358097556312).

Almost surely, 2^{1432322034133} is an apocalyptic number.

It is an amenable number.

1432322034133 is a deficient number, since it is larger than the sum of its proper divisors (68191115).

1432322034133 is an equidigital number, since it uses as much as digits as its factorization.

1432322034133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68191114.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1432322034133 its reverse (3314302232341), we get a palindrome (4746624266474).

The spelling of 1432322034133 in words is "one trillion, four hundred thirty-two billion, three hundred twenty-two million, thirty-four thousand, one hundred thirty-three".