Base | Representation |
---|---|
bin | 1101000001101110001001… |
… | …1110001100110011100111 |
3 | 1212201021201212101020202012 |
4 | 3100123202132030303213 |
5 | 3334132423424014310 |
6 | 50243555140504435 |
7 | 3005550520504322 |
oct | 320334236146347 |
9 | 55637655336665 |
10 | 14323220532455 |
11 | 462249764867a |
12 | 1733b296ab11b |
13 | 7cb89b737893 |
14 | 3773674a77b9 |
15 | 19c8a6e2ec05 |
hex | d06e278cce7 |
14323220532455 has 8 divisors (see below), whose sum is σ = 17607080849904. Its totient is φ = 11179098952000.
The previous prime is 14323220532449. The next prime is 14323220532479. The reversal of 14323220532455 is 55423502232341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-14323220532455 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34934684021 + ... + 34934684430.
It is an arithmetic number, because the mean of its divisors is an integer number (2200885106238).
Almost surely, 214323220532455 is an apocalyptic number.
14323220532455 is a deficient number, since it is larger than the sum of its proper divisors (3283860317449).
14323220532455 is an equidigital number, since it uses as much as digits as its factorization.
14323220532455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69869368497.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 14323220532455 its reverse (55423502232341), we get a palindrome (69746722764796).
The spelling of 14323220532455 in words is "fourteen trillion, three hundred twenty-three billion, two hundred twenty million, five hundred thirty-two thousand, four hundred fifty-five".
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