Base | Representation |
---|---|
bin | 1000010101101001101… |
… | …1110001110111010101 |
3 | 111200202102022112022212 |
4 | 2011122123301313111 |
5 | 4321334243333331 |
6 | 145450401203205 |
7 | 13230616463363 |
oct | 2053233616725 |
9 | 450672275285 |
10 | 143251152341 |
11 | 558305a5000 |
12 | 2391a630505 |
13 | 1067c30058b |
14 | 6d0d330633 |
15 | 3ad6375d2b |
hex | 215a6f1dd5 |
143251152341 has 32 divisors (see below), whose sum is σ = 168488574336. Its totient is φ = 121352352000.
The previous prime is 143251152337. The next prime is 143251152349.
143251152341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 143251152341 - 22 = 143251152337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143251152298 and 143251152307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143251152349) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2253986 + ... + 2316668.
It is an arithmetic number, because the mean of its divisors is an integer number (5265267948).
Almost surely, 2143251152341 is an apocalyptic number.
143251152341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
143251152341 is a deficient number, since it is larger than the sum of its proper divisors (25237421995).
143251152341 is a wasteful number, since it uses less digits than its factorization.
143251152341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62834 (or 62812 counting only the distinct ones).
The product of its digits is 14400, while the sum is 32.
It can be divided in two parts, 143251 and 152341, that added together give a palindrome (295592).
The spelling of 143251152341 in words is "one hundred forty-three billion, two hundred fifty-one million, one hundred fifty-two thousand, three hundred forty-one".
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