14325410001132 has 36 divisors (see below), whose sum is σ = 38117319010680. Its totient is φ = 4523813684352.

The previous prime is 14325410001073. The next prime is 14325410001169. The reversal of 14325410001132 is 23110001452341.

14325410001132 is a `hidden beast` number, since 1 + 4 + 3 + 2 + 541 + 0 + 0 + 0 + 113 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (36).

It is a junction number, because it is equal to n+sod(n) for n = 14325410001096 and 14325410001105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10471790253 + ... + 10471791620.

Almost surely, 2^{14325410001132} is an apocalyptic number.

14325410001132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14325410001132 is an abundant number, since it is smaller than the sum of its proper divisors (23791909009548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14325410001132 is a wasteful number, since it uses less digits than its factorization.

14325410001132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20943581902 (or 20943581897 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 14325410001132 its reverse (23110001452341), we get a palindrome (37435411453473).

The spelling of 14325410001132 in words is "fourteen trillion, three hundred twenty-five billion, four hundred ten million, one thousand, one hundred thirty-two".