Base | Representation |
---|---|
bin | 1101000010000111110111… |
… | …1001001110110101101101 |
3 | 1212201221112220200200211210 |
4 | 3100201331321032311231 |
5 | 3334241043000220240 |
6 | 50251100113505033 |
7 | 3006213544124202 |
oct | 320417571166555 |
9 | 55657486620753 |
10 | 14330123054445 |
11 | 4625409973600 |
12 | 1735335272179 |
13 | 7cc42b7a0c13 |
14 | 3778200cbca9 |
15 | 19cb5cde1780 |
hex | d087de4ed6d |
14330123054445 has 24 divisors (see below), whose sum is σ = 25202067655968. Its totient is φ = 6947938449760.
The previous prime is 14330123054431. The next prime is 14330123054461. The reversal of 14330123054445 is 54445032103341.
It is not a de Polignac number, because 14330123054445 - 25 = 14330123054413 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3947690487 + ... + 3947694116.
It is an arithmetic number, because the mean of its divisors is an integer number (1050086152332).
Almost surely, 214330123054445 is an apocalyptic number.
14330123054445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14330123054445 is a deficient number, since it is larger than the sum of its proper divisors (10871944601523).
14330123054445 is a wasteful number, since it uses less digits than its factorization.
14330123054445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7895384633 (or 7895384622 counting only the distinct ones).
The product of its (nonzero) digits is 345600, while the sum is 39.
Adding to 14330123054445 its reverse (54445032103341), we get a palindrome (68775155157786).
The spelling of 14330123054445 in words is "fourteen trillion, three hundred thirty billion, one hundred twenty-three million, fifty-four thousand, four hundred forty-five".
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