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1433200012102 = 2716600006051
BaseRepresentation
bin10100110110110001011…
…000001010101101000110
312002000100011200011012201
4110312301120022231012
5141440143200341402
63014223014105114
7205355014046155
oct24666130125506
95060304604181
101433200012102
115028a9052821
121b191b94b19a
13a51c4c43151
144d51da4359c
1527432b8a687
hex14db160ab46

1433200012102 has 4 divisors (see below), whose sum is σ = 2149800018156. Its totient is φ = 716600006050.

The previous prime is 1433200012087. The next prime is 1433200012103. The reversal of 1433200012102 is 2012100023341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1433200012102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1433200012103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 358300003024 + ... + 358300003027.

It is an arithmetic number, because the mean of its divisors is an integer number (537450004539).

Almost surely, 21433200012102 is an apocalyptic number.

1433200012102 is a deficient number, since it is larger than the sum of its proper divisors (716600006054).

1433200012102 is an equidigital number, since it uses as much as digits as its factorization.

1433200012102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 716600006053.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 1433200012102 its reverse (2012100023341), we get a palindrome (3445300035443).

The spelling of 1433200012102 in words is "one trillion, four hundred thirty-three billion, two hundred million, twelve thousand, one hundred two".

Divisors: 1 2 716600006051 1433200012102