14332044011 has 4 divisors (see below), whose sum is σ = 14332307400. Its totient is φ = 14331780624.

The previous prime is 14332043993. The next prime is 14332044037. The reversal of 14332044011 is 11044023341.

14332044011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11044023341 = 13 ⋅849540257.

It is a cyclic number.

It is not a de Polignac number, because 14332044011 - 2¹⁰ = 14332042987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14332044061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16466 + ... + 170103.

It is an arithmetic number, because the mean of its divisors is an integer number (3583076850).

Almost surely, 2^14332044011 is an apocalyptic number.

14332044011 is a deficient number, since it is larger than the sum of its proper divisors (263389).

14332044011 is an equidigital number, since it uses as much as digits as its factorization.

14332044011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 263388.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14332044011 its reverse (11044023341), we get a palindrome (25376067352).

The spelling of 14332044011 in words is "fourteen billion, three hundred thirty-two million, forty-four thousand, eleven".