Search a number
-
+
14340434111 = 139910250489
BaseRepresentation
bin11010101101100000…
…11010100010111111
31101000102001112101022
431112300122202333
5213332122342421
610330553134355
71015240451543
oct152660324277
941012045338
1014340434111
11609988a443
1229426ba3bb
131476cc5c93
149a07b3a23
1558de7c7ab
hex356c1a8bf

14340434111 has 4 divisors (see below), whose sum is σ = 14350686000. Its totient is φ = 14330182224.

The previous prime is 14340434021. The next prime is 14340434123. The reversal of 14340434111 is 11143404341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14340434111 - 226 = 14273325247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14340434011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5123846 + ... + 5126643.

It is an arithmetic number, because the mean of its divisors is an integer number (3587671500).

Almost surely, 214340434111 is an apocalyptic number.

14340434111 is a deficient number, since it is larger than the sum of its proper divisors (10251889).

14340434111 is a wasteful number, since it uses less digits than its factorization.

14340434111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10251888.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 14340434111 its reverse (11143404341), we get a palindrome (25483838452).

It can be divided in two parts, 143404341 and 11, that multiplied together give a palindrome (1577447751).

The spelling of 14340434111 in words is "fourteen billion, three hundred forty million, four hundred thirty-four thousand, one hundred eleven".

Divisors: 1 1399 10250489 14340434111