Base | Representation |
---|---|
bin | 1101000010110000110011… |
… | …1010110101101101110001 |
3 | 1212202222220210101000212001 |
4 | 3100230030322311231301 |
5 | 3334431044303133210 |
6 | 50300114404534001 |
7 | 3010053065246440 |
oct | 320541472655561 |
9 | 55688823330761 |
10 | 14341112552305 |
11 | 462a039188a40 |
12 | 17374a16b1301 |
13 | 80049048c286 |
14 | 378183826d57 |
15 | 19d0a2aa903a |
hex | d0b0ceb5b71 |
14341112552305 has 32 divisors (see below), whose sum is σ = 21510950872320. Its totient is φ = 8916932440320.
The previous prime is 14341112552269. The next prime is 14341112552309. The reversal of 14341112552305 is 50325521114341.
It is not a de Polignac number, because 14341112552305 - 211 = 14341112550257 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14341112552309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47728954 + ... + 48028483.
It is an arithmetic number, because the mean of its divisors is an integer number (672217214760).
Almost surely, 214341112552305 is an apocalyptic number.
It is an amenable number.
14341112552305 is a deficient number, since it is larger than the sum of its proper divisors (7169838320015).
14341112552305 is a wasteful number, since it uses less digits than its factorization.
14341112552305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95757849.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 14341112552305 its reverse (50325521114341), we get a palindrome (64666633666646).
The spelling of 14341112552305 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, five hundred fifty-two thousand, three hundred five".
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