Base | Representation |
---|---|
bin | 1101000010110001101010… |
… | …0110101101000110110111 |
3 | 1212210000111210102001210122 |
4 | 3100230122212231012313 |
5 | 3334432032042431231 |
6 | 50300153250042155 |
7 | 3010061553656552 |
oct | 320543246550667 |
9 | 55700453361718 |
10 | 14341342155191 |
11 | 462a14684aa97 |
12 | 173754657935b |
13 | 8004c8c0c87c |
14 | 3781a6113699 |
15 | 19d0b7d0e77b |
hex | d0b1a9ad1b7 |
14341342155191 has 2 divisors, whose sum is σ = 14341342155192. Its totient is φ = 14341342155190.
The previous prime is 14341342155121. The next prime is 14341342155193. The reversal of 14341342155191 is 19155124314341.
It is a strong prime.
It is an emirp because it is prime and its reverse (19155124314341) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14341342155191 is a prime.
Together with 14341342155193, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14341342155193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170671077595 + 7170671077596.
It is an arithmetic number, because the mean of its divisors is an integer number (7170671077596).
Almost surely, 214341342155191 is an apocalyptic number.
14341342155191 is a deficient number, since it is larger than the sum of its proper divisors (1).
14341342155191 is an equidigital number, since it uses as much as digits as its factorization.
14341342155191 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 259200, while the sum is 44.
The spelling of 14341342155191 in words is "fourteen trillion, three hundred forty-one billion, three hundred forty-two million, one hundred fifty-five thousand, one hundred ninety-one".
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