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14341342155191 is a prime number
BaseRepresentation
bin1101000010110001101010…
…0110101101000110110111
31212210000111210102001210122
43100230122212231012313
53334432032042431231
650300153250042155
73010061553656552
oct320543246550667
955700453361718
1014341342155191
11462a14684aa97
12173754657935b
138004c8c0c87c
143781a6113699
1519d0b7d0e77b
hexd0b1a9ad1b7

14341342155191 has 2 divisors, whose sum is σ = 14341342155192. Its totient is φ = 14341342155190.

The previous prime is 14341342155121. The next prime is 14341342155193. The reversal of 14341342155191 is 19155124314341.

It is a strong prime.

It is an emirp because it is prime and its reverse (19155124314341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14341342155191 is a prime.

Together with 14341342155193, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14341342155193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170671077595 + 7170671077596.

It is an arithmetic number, because the mean of its divisors is an integer number (7170671077596).

Almost surely, 214341342155191 is an apocalyptic number.

14341342155191 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341342155191 is an equidigital number, since it uses as much as digits as its factorization.

14341342155191 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 259200, while the sum is 44.

The spelling of 14341342155191 in words is "fourteen trillion, three hundred forty-one billion, three hundred forty-two million, one hundred fifty-five thousand, one hundred ninety-one".