Search a number
-
+
143431207 is a prime number
BaseRepresentation
bin10001000110010…
…01011000100111
3100222220001121221
420203021120213
5243204244312
622122121211
73361100533
oct1043113047
9328801557
10143431207
1173a65a97
1240050207
132393c04a
1415098bc3
15c8d3207
hex88c9627

143431207 has 2 divisors, whose sum is σ = 143431208. Its totient is φ = 143431206.

The previous prime is 143431201. The next prime is 143431213. The reversal of 143431207 is 702134341.

It is a balanced prime because it is at equal distance from previous prime (143431201) and next prime (143431213).

It is a cyclic number.

It is not a de Polignac number, because 143431207 - 23 = 143431199 is a prime.

It is a super-2 number, since 2×1434312072 = 41145022282953698, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143431201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71715603 + 71715604.

It is an arithmetic number, because the mean of its divisors is an integer number (71715604).

Almost surely, 2143431207 is an apocalyptic number.

143431207 is a deficient number, since it is larger than the sum of its proper divisors (1).

143431207 is an equidigital number, since it uses as much as digits as its factorization.

143431207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 143431207 is about 11976.2768421576. The cubic root of 143431207 is about 523.4572481216.

Adding to 143431207 its reverse (702134341), we get a palindrome (845565548).

The spelling of 143431207 in words is "one hundred forty-three million, four hundred thirty-one thousand, two hundred seven".