14343311334341 has 4 divisors (see below), whose sum is σ = 15647248728384. Its totient is φ = 13039373940300.

The previous prime is 14343311334311. The next prime is 14343311334377.

14343311334341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14343311334341 - 2⁶ = 14343311334277 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14343311334295 and 14343311334304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14343311334311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 651968697005 + ... + 651968697026.

It is an arithmetic number, because the mean of its divisors is an integer number (3911812182096).

Almost surely, 2^{14343311334341} is an apocalyptic number.

14343311334341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14343311334341 is a deficient number, since it is larger than the sum of its proper divisors (1303937394043).

14343311334341 is a wasteful number, since it uses less digits than its factorization.

14343311334341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1303937394042.

The product of its digits is 186624, while the sum is 38.

It can be divided in two parts, 1434331 and 1334341, that added together give a palindrome (2768672).

The spelling of 14343311334341 in words is "fourteen trillion, three hundred forty-three billion, three hundred eleven million, three hundred thirty-four thousand, three hundred forty-one".