14343314351 has 2 divisors, whose sum is σ = 14343314352. Its totient is φ = 14343314350.

The previous prime is 14343314327. The next prime is 14343314353. The reversal of 14343314351 is 15341334341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14343314351 - 2⁶ = 14343314287 is a prime.

Together with 14343314353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14343314353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171657175 + 7171657176.

It is an arithmetic number, because the mean of its divisors is an integer number (7171657176).

Almost surely, 2^14343314351 is an apocalyptic number.

14343314351 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343314351 is an equidigital number, since it uses as much as digits as its factorization.

14343314351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25920, while the sum is 32.

Adding to 14343314351 its reverse (15341334341), we get a palindrome (29684648692).

The spelling of 14343314351 in words is "fourteen billion, three hundred forty-three million, three hundred fourteen thousand, three hundred fifty-one".