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14344314221 is a prime number
BaseRepresentation
bin11010101101111110…
…01101110101101101
31101000200100122220002
431112333031311231
5213334121023341
610331212234045
71015315442036
oct152677156555
941020318802
1014344314221
1160a0a9a646
122943a6b925
131477a540c3
149a1103a8d
1558e49729b
hex356fcdd6d

14344314221 has 2 divisors, whose sum is σ = 14344314222. Its totient is φ = 14344314220.

The previous prime is 14344314211. The next prime is 14344314223. The reversal of 14344314221 is 12241344341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9459702121 + 4884612100 = 97261^2 + 69890^2 .

It is an emirp because it is prime and its reverse (12241344341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14344314221 - 218 = 14344052077 is a prime.

Together with 14344314223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14344314223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172157110 + 7172157111.

It is an arithmetic number, because the mean of its divisors is an integer number (7172157111).

Almost surely, 214344314221 is an apocalyptic number.

It is an amenable number.

14344314221 is a deficient number, since it is larger than the sum of its proper divisors (1).

14344314221 is an equidigital number, since it uses as much as digits as its factorization.

14344314221 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9216, while the sum is 29.

Adding to 14344314221 its reverse (12241344341), we get a palindrome (26585658562).

The spelling of 14344314221 in words is "fourteen billion, three hundred forty-four million, three hundred fourteen thousand, two hundred twenty-one".