14354040341 has 2 divisors, whose sum is σ = 14354040342. Its totient is φ = 14354040340.

The previous prime is 14354040331. The next prime is 14354040343. The reversal of 14354040341 is 14304045341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13955878225 + 398162116 = 118135^2 + 19954^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354040341 - 2³⁰ = 13280298517 is a prime.

It is a super-2 number, since 2×14354040341² (a number of 21 digits) contains 22 as substring.

Together with 14354040343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14354040343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177020170 + 7177020171.

It is an arithmetic number, because the mean of its divisors is an integer number (7177020171).

Almost surely, 2^14354040341 is an apocalyptic number.

It is an amenable number.

14354040341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354040341 is an equidigital number, since it uses as much as digits as its factorization.

14354040341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 14354040341 its reverse (14304045341), we get a palindrome (28658085682).

Subtracting from 14354040341 its reverse (14304045341), we obtain a triangular number (49995000 = T₉₉₉₉).

The spelling of 14354040341 in words is "fourteen billion, three hundred fifty-four million, forty thousand, three hundred forty-one".