Search a number
-
+
1440020130204 = 223120001677517
BaseRepresentation
bin10100111101000111111…
…000110110100110011100
312002122221110221001102110
4110331013320312212130
5142043130123131304
63021311444554020
7206016020101335
oct24750770664634
95078843831373
101440020130204
11505788905467
121b31039b2910
13a5a40bb6ba6
144d9a973728c
15276d17c1289
hex14f47e3699c

1440020130204 has 12 divisors (see below), whose sum is σ = 3360046970504. Its totient is φ = 480006710064.

The previous prime is 1440020130187. The next prime is 1440020130247. The reversal of 1440020130204 is 4020310200441.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×14400201302042 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60000838747 + ... + 60000838770.

Almost surely, 21440020130204 is an apocalyptic number.

It is an amenable number.

1440020130204 is an abundant number, since it is smaller than the sum of its proper divisors (1920026840300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1440020130204 is a wasteful number, since it uses less digits than its factorization.

1440020130204 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120001677524 (or 120001677522 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 1440020130204 its reverse (4020310200441), we get a palindrome (5460330330645).

The spelling of 1440020130204 in words is "one trillion, four hundred forty billion, twenty million, one hundred thirty thousand, two hundred four".

Divisors: 1 2 3 4 6 12 120001677517 240003355034 360005032551 480006710068 720010065102 1440020130204