Base | Representation |
---|---|
bin | 11010110100101111… |
… | …00010011000001011 |
3 | 1101011122001200120212 |
4 | 31122113202120023 |
5 | 213443130141301 |
6 | 10340555511335 |
7 | 1016604443165 |
oct | 153227423013 |
9 | 41148050525 |
10 | 14401021451 |
11 | 6120001623 |
12 | 295aa5854b |
13 | 148671a38b |
14 | 9a8865935 |
15 | 5944494bb |
hex | 35a5e260b |
14401021451 has 2 divisors, whose sum is σ = 14401021452. Its totient is φ = 14401021450.
The previous prime is 14401021423. The next prime is 14401021493. The reversal of 14401021451 is 15412010441.
14401021451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14401021451 is a prime.
It is not a weakly prime, because it can be changed into another prime (14401021651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200510725 + 7200510726.
It is an arithmetic number, because the mean of its divisors is an integer number (7200510726).
Almost surely, 214401021451 is an apocalyptic number.
14401021451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14401021451 is an equidigital number, since it uses as much as digits as its factorization.
14401021451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 640, while the sum is 23.
Adding to 14401021451 its reverse (15412010441), we get a palindrome (29813031892).
The spelling of 14401021451 in words is "fourteen billion, four hundred one million, twenty-one thousand, four hundred fifty-one".
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