Base | Representation |
---|---|
bin | 11010110100110000… |
… | …10000110010011110 |
3 | 1101011122102100100120 |
4 | 31122120100302132 |
5 | 213443202232200 |
6 | 10341003535410 |
7 | 1016606164335 |
oct | 153230206236 |
9 | 41148370316 |
10 | 14401211550 |
11 | 6120121430 |
12 | 295ab2a566 |
13 | 1486785a6b |
14 | 9a88b4d1c |
15 | 5944859a0 |
hex | 35a610c9e |
14401211550 has 96 divisors (see below), whose sum is σ = 39307127040. Its totient is φ = 3460262400.
The previous prime is 14401211537. The next prime is 14401211551. The reversal of 14401211550 is 5511210441.
It is a super-3 number, since 3×144012115503 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14401211550.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14401211551) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 147831 + ... + 225069.
It is an arithmetic number, because the mean of its divisors is an integer number (409449240).
Almost surely, 214401211550 is an apocalyptic number.
14401211550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 14401211550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19653563520).
14401211550 is an abundant number, since it is smaller than the sum of its proper divisors (24905915490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14401211550 is a wasteful number, since it uses less digits than its factorization.
14401211550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77378 (or 77373 counting only the distinct ones).
The product of its (nonzero) digits is 800, while the sum is 24.
Adding to 14401211550 its reverse (5511210441), we get a palindrome (19912421991).
The spelling of 14401211550 in words is "fourteen billion, four hundred one million, two hundred eleven thousand, five hundred fifty".
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