1440131211301 has 2 divisors, whose sum is σ = 1440131211302. Its totient is φ = 1440131211300.

The previous prime is 1440131211287. The next prime is 1440131211329. The reversal of 1440131211301 is 1031121310441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1435551441025 + 4579770276 = 1198145^2 + 67674^2 .

It is a cyclic number.

It is not a de Polignac number, because 1440131211301 - 2⁹ = 1440131210789 is a prime.

It is a super-2 number, since 2×1440131211301² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1440131211391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065605650 + 720065605651.

It is an arithmetic number, because the mean of its divisors is an integer number (720065605651).

Almost surely, 2^{1440131211301} is an apocalyptic number.

It is an amenable number.

1440131211301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440131211301 is an equidigital number, since it uses as much as digits as its factorization.

1440131211301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1440131211301 its reverse (1031121310441), we get a palindrome (2471252521742).

The spelling of 1440131211301 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, two hundred eleven thousand, three hundred one".