Base | Representation |
---|---|
bin | 10100111110011011010… |
… | …110100101011011011011 |
3 | 12002210120001211210220020 |
4 | 110332123112211123123 |
5 | 142104012112324430 |
6 | 3022102430201523 |
7 | 206065512345165 |
oct | 24763326453333 |
9 | 5083501753806 |
10 | 1441420433115 |
11 | 5063372907a3 |
12 | 1b34349532a3 |
13 | a5c050404b0 |
14 | 4da9d6c7935 |
15 | 277646c5b10 |
hex | 14f9b5a56db |
1441420433115 has 64 divisors (see below), whose sum is σ = 2488427246592. Its totient is φ = 708266995200.
The previous prime is 1441420433113. The next prime is 1441420433129. The reversal of 1441420433115 is 5113340241441.
It is not a de Polignac number, because 1441420433115 - 21 = 1441420433113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1441420433113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 273979585 + ... + 273984845.
It is an arithmetic number, because the mean of its divisors is an integer number (38881675728).
Almost surely, 21441420433115 is an apocalyptic number.
1441420433115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1441420433115 is a deficient number, since it is larger than the sum of its proper divisors (1047006813477).
1441420433115 is a wasteful number, since it uses less digits than its factorization.
1441420433115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7700.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 1441420433115 its reverse (5113340241441), we get a palindrome (6554760674556).
The spelling of 1441420433115 in words is "one trillion, four hundred forty-one billion, four hundred twenty million, four hundred thirty-three thousand, one hundred fifteen".
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