14431103411 has 2 divisors, whose sum is σ = 14431103412. Its totient is φ = 14431103410.

The previous prime is 14431103399. The next prime is 14431103413. The reversal of 14431103411 is 11430113441.

14431103411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14431103411 - 2⁶ = 14431103347 is a prime.

Together with 14431103413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14431103413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7215551705 + 7215551706.

It is an arithmetic number, because the mean of its divisors is an integer number (7215551706).

Almost surely, 2^14431103411 is an apocalyptic number.

14431103411 is a deficient number, since it is larger than the sum of its proper divisors (1).

14431103411 is an equidigital number, since it uses as much as digits as its factorization.

14431103411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14431103411 its reverse (11430113441), we get a palindrome (25861216852).

The spelling of 14431103411 in words is "fourteen billion, four hundred thirty-one million, one hundred three thousand, four hundred eleven".