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14431132420535 = 52886226484107
BaseRepresentation
bin1101001000000000001010…
…0001011000100110110111
31220002121021102122011001202
43102000002201120212313
53342414424344424120
650405323135043115
73016420625433035
oct322000241304667
956077242564052
1014431132420535
11466423303a356
121750a2507049b
13808b084499ac
1437c683217555
151a05c0a5c875
hexd20028589b7

14431132420535 has 4 divisors (see below), whose sum is σ = 17317358904648. Its totient is φ = 11544905936424.

The previous prime is 14431132420517. The next prime is 14431132420547. The reversal of 14431132420535 is 53502423113441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14431132420535 - 226 = 14431065311671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1443113242049 + ... + 1443113242058.

It is an arithmetic number, because the mean of its divisors is an integer number (4329339726162).

Almost surely, 214431132420535 is an apocalyptic number.

14431132420535 is a deficient number, since it is larger than the sum of its proper divisors (2886226484113).

14431132420535 is an equidigital number, since it uses as much as digits as its factorization.

14431132420535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2886226484112.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 14431132420535 its reverse (53502423113441), we get a palindrome (67933555533976).

The spelling of 14431132420535 in words is "fourteen trillion, four hundred thirty-one billion, one hundred thirty-two million, four hundred twenty thousand, five hundred thirty-five".

Divisors: 1 5 2886226484107 14431132420535