Base | Representation |
---|---|
bin | 1000011001101011001… |
… | …1011111111001110101 |
3 | 111210112200110011112201 |
4 | 2012122303133321311 |
5 | 4331042231041203 |
6 | 150145500344501 |
7 | 13266442132102 |
oct | 2063263377165 |
9 | 453480404481 |
10 | 144331112053 |
11 | 56235171797 |
12 | 23b80245131 |
13 | 107c1c856ab |
14 | 6db2933aa9 |
15 | 3b4b09de1d |
hex | 219acdfe75 |
144331112053 has 2 divisors, whose sum is σ = 144331112054. Its totient is φ = 144331112052.
The previous prime is 144331112017. The next prime is 144331112171. The reversal of 144331112053 is 350211133441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74285137809 + 70045974244 = 272553^2 + 264662^2 .
It is a cyclic number.
It is not a de Polignac number, because 144331112053 - 29 = 144331111541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144331113053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72165556026 + 72165556027.
It is an arithmetic number, because the mean of its divisors is an integer number (72165556027).
Almost surely, 2144331112053 is an apocalyptic number.
It is an amenable number.
144331112053 is a deficient number, since it is larger than the sum of its proper divisors (1).
144331112053 is an equidigital number, since it uses as much as digits as its factorization.
144331112053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 144331112053 its reverse (350211133441), we get a palindrome (494542245494).
The spelling of 144331112053 in words is "one hundred forty-four billion, three hundred thirty-one million, one hundred twelve thousand, fifty-three".
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