Base | Representation |
---|---|
bin | 1000011001101011001… |
… | …1011111111011101011 |
3 | 111210112200110011201002 |
4 | 2012122303133323223 |
5 | 4331042231042141 |
6 | 150145500345215 |
7 | 13266442132331 |
oct | 2063263377353 |
9 | 453480404632 |
10 | 144331112171 |
11 | 56235171894 |
12 | 23b8024520b |
13 | 107c1c8576c |
14 | 6db2933b51 |
15 | 3b4b09de9b |
hex | 219acdfeeb |
144331112171 has 2 divisors, whose sum is σ = 144331112172. Its totient is φ = 144331112170.
The previous prime is 144331112053. The next prime is 144331112173. The reversal of 144331112171 is 171211133441.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144331112171 is a prime.
Together with 144331112173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (144331112173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72165556085 + 72165556086.
It is an arithmetic number, because the mean of its divisors is an integer number (72165556086).
Almost surely, 2144331112171 is an apocalyptic number.
144331112171 is a deficient number, since it is larger than the sum of its proper divisors (1).
144331112171 is an equidigital number, since it uses as much as digits as its factorization.
144331112171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2016, while the sum is 29.
The spelling of 144331112171 in words is "one hundred forty-four billion, three hundred thirty-one million, one hundred twelve thousand, one hundred seventy-one".
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