1443424131231 has 4 divisors (see below), whose sum is σ = 1924565508312. Its totient is φ = 962282754152.

The previous prime is 1443424131221. The next prime is 1443424131239. The reversal of 1443424131231 is 1321314243441.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1443424131231 - 2¹⁰ = 1443424130207 is a prime.

It is a super-2 number, since 2×1443424131231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1443424131192 and 1443424131201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1443424131239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240570688536 + ... + 240570688541.

It is an arithmetic number, because the mean of its divisors is an integer number (481141377078).

Almost surely, 2^{1443424131231} is an apocalyptic number.

1443424131231 is a deficient number, since it is larger than the sum of its proper divisors (481141377081).

1443424131231 is an equidigital number, since it uses as much as digits as its factorization.

1443424131231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 481141377080.

The product of its digits is 27648, while the sum is 33.

Adding to 1443424131231 its reverse (1321314243441), we get a palindrome (2764738374672).

The spelling of 1443424131231 in words is "one trillion, four hundred forty-three billion, four hundred twenty-four million, one hundred thirty-one thousand, two hundred thirty-one".