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144404202013 is a prime number
BaseRepresentation
bin1000011001111100101…
…0010100001000011101
3111210201202222112010021
42012133022110020131
54331214433431023
6150201031112141
713301320315261
oct2063712241035
9453652875107
10144404202013
1156272453315
1223ba0812651
13108041667a6
146dbc51c0a1
153b526da35d
hex219f29421d

144404202013 has 2 divisors, whose sum is σ = 144404202014. Its totient is φ = 144404202012.

The previous prime is 144404202011. The next prime is 144404202017. The reversal of 144404202013 is 310202404441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98836041924 + 45568160089 = 314382^2 + 213467^2 .

It is a cyclic number.

It is not a de Polignac number, because 144404202013 - 21 = 144404202011 is a prime.

It is a super-2 number, since 2×1444042020132 (a number of 23 digits) contains 22 as substring.

Together with 144404202011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144404202011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72202101006 + 72202101007.

It is an arithmetic number, because the mean of its divisors is an integer number (72202101007).

Almost surely, 2144404202013 is an apocalyptic number.

It is an amenable number.

144404202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

144404202013 is an equidigital number, since it uses as much as digits as its factorization.

144404202013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 144404202013 its reverse (310202404441), we get a palindrome (454606606454).

The spelling of 144404202013 in words is "one hundred forty-four billion, four hundred four million, two hundred two thousand, thirteen".