Base | Representation |
---|---|
bin | 101011001100101… |
… | …1111000000110111 |
3 | 10202000112022021122 |
4 | 1112121133000313 |
5 | 10432034134312 |
6 | 355500134155 |
7 | 50630504231 |
oct | 12631370067 |
9 | 3660468248 |
10 | 1449521207 |
11 | 684242812 |
12 | 34553735b |
13 | 1a13c9c74 |
14 | da723251 |
15 | 873c7b72 |
hex | 5665f037 |
1449521207 has 2 divisors, whose sum is σ = 1449521208. Its totient is φ = 1449521206.
The previous prime is 1449521137. The next prime is 1449521209. The reversal of 1449521207 is 7021259441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1449521207 - 220 = 1448472631 is a prime.
It is a super-2 number, since 2×14495212072 = 4202223459085473698, which contains 22 as substring.
Together with 1449521209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1449521209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 724760603 + 724760604.
It is an arithmetic number, because the mean of its divisors is an integer number (724760604).
Almost surely, 21449521207 is an apocalyptic number.
1449521207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1449521207 is an equidigital number, since it uses as much as digits as its factorization.
1449521207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
The square root of 1449521207 is about 38072.5781501595. The cubic root of 1449521207 is about 1131.7266023794.
The spelling of 1449521207 in words is "one billion, four hundred forty-nine million, five hundred twenty-one thousand, two hundred seven".
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