Base | Representation |
---|---|
bin | 1000011100001011001… |
… | …0110001101011001111 |
3 | 111212021102212101100120 |
4 | 2013002302301223033 |
5 | 4333431003330333 |
6 | 150340224200023 |
7 | 13322166521520 |
oct | 2070262615317 |
9 | 455242771316 |
10 | 145002011343 |
11 | 56549945312 |
12 | 24128a69013 |
13 | 1089ac76217 |
14 | 7037a94847 |
15 | 3b89e23db3 |
hex | 21c2cb1acf |
145002011343 has 64 divisors (see below), whose sum is σ = 240880324608. Its totient is φ = 75694510080.
The previous prime is 145002011311. The next prime is 145002011369. The reversal of 145002011343 is 343110200541.
It is a happy number.
145002011343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 145002011343 - 25 = 145002011311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145002011303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2858346 + ... + 2908632.
It is an arithmetic number, because the mean of its divisors is an integer number (3763755072).
Almost surely, 2145002011343 is an apocalyptic number.
145002011343 is a deficient number, since it is larger than the sum of its proper divisors (95878313265).
145002011343 is a wasteful number, since it uses less digits than its factorization.
145002011343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50552.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 145002011343 its reverse (343110200541), we get a palindrome (488112211884).
The spelling of 145002011343 in words is "one hundred forty-five billion, two million, eleven thousand, three hundred forty-three".
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