1451330112541 has 2 divisors, whose sum is σ = 1451330112542. Its totient is φ = 1451330112540.

The previous prime is 1451330112539. The next prime is 1451330112611. The reversal of 1451330112541 is 1452110331541.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1411294104441 + 40036008100 = 1187979^2 + 200090^2 .

It is a cyclic number.

It is not a de Polignac number, because 1451330112541 - 2¹ = 1451330112539 is a prime.

It is a super-3 number, since 3×1451330112541³ (a number of 37 digits) contains 333 as substring.

Together with 1451330112539, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1451330112941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725665056270 + 725665056271.

It is an arithmetic number, because the mean of its divisors is an integer number (725665056271).

Almost surely, 2^{1451330112541} is an apocalyptic number.

It is an amenable number.

1451330112541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1451330112541 is an equidigital number, since it uses as much as digits as its factorization.

1451330112541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

The spelling of 1451330112541 in words is "one trillion, four hundred fifty-one billion, three hundred thirty million, one hundred twelve thousand, five hundred forty-one".