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145134131 is a prime number
BaseRepresentation
bin10001010011010…
…01001000110011
3101010002120121012
420221221020303
5244123243011
622222421135
73411422402
oct1051511063
9333076535
10145134131
1174a1946a
12407317ab
13240b71ac
14153bd639
15cb1ca8b
hex8a69233

145134131 has 2 divisors, whose sum is σ = 145134132. Its totient is φ = 145134130.

The previous prime is 145134089. The next prime is 145134133. The reversal of 145134131 is 131431541.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145134131 - 214 = 145117747 is a prime.

It is a super-2 number, since 2×1451341312 = 42127831962250322, which contains 22 as substring.

Together with 145134133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 145134097 and 145134106.

It is not a weakly prime, because it can be changed into another prime (145134133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72567065 + 72567066.

It is an arithmetic number, because the mean of its divisors is an integer number (72567066).

Almost surely, 2145134131 is an apocalyptic number.

145134131 is a deficient number, since it is larger than the sum of its proper divisors (1).

145134131 is an equidigital number, since it uses as much as digits as its factorization.

145134131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 23.

The square root of 145134131 is about 12047.1627780154. The cubic root of 145134131 is about 525.5207301973.

Adding to 145134131 its reverse (131431541), we get a palindrome (276565672).

The spelling of 145134131 in words is "one hundred forty-five million, one hundred thirty-four thousand, one hundred thirty-one".