Base | Representation |
---|---|
bin | 10101001000010111111… |
… | …010010111011010001111 |
3 | 12010211010100120020020110 |
4 | 111020113322113122033 |
5 | 142242400112403010 |
6 | 3031030253051103 |
7 | 206624252246136 |
oct | 25102772273217 |
9 | 5124110506213 |
10 | 1452100122255 |
11 | 50a917732272 |
12 | 1b5515486a93 |
13 | a6c177a8293 |
14 | 503d3c1891d |
15 | 27b8c093120 |
hex | 15217e9768f |
1452100122255 has 24 divisors (see below), whose sum is σ = 2378648423088. Its totient is φ = 756442839936.
The previous prime is 1452100122211. The next prime is 1452100122293. The reversal of 1452100122255 is 5522210012541.
It is not a de Polignac number, because 1452100122255 - 27 = 1452100122127 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26150382 + ... + 26205851.
It is an arithmetic number, because the mean of its divisors is an integer number (99110350962).
Almost surely, 21452100122255 is an apocalyptic number.
1452100122255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1452100122255 is a deficient number, since it is larger than the sum of its proper divisors (926548300833).
1452100122255 is an equidigital number, since it uses as much as digits as its factorization.
1452100122255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52356327 (or 52356284 counting only the distinct ones).
The product of its (nonzero) digits is 8000, while the sum is 30.
Adding to 1452100122255 its reverse (5522210012541), we get a palindrome (6974310134796).
The spelling of 1452100122255 in words is "one trillion, four hundred fifty-two billion, one hundred million, one hundred twenty-two thousand, two hundred fifty-five".
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