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145305365335 = 5132235467159
BaseRepresentation
bin1000011101010011011…
…1111110101101010111
3111220001120200100210121
42013110313332231113
54340041133142320
6150430302132411
713332542140504
oct2072467765527
9456046610717
10145305365335
11566950aa699
12241b2581107
1310918a79820
14706609c4ab
153ba68968aa
hex21d4dfeb57

145305365335 has 8 divisors (see below), whose sum is σ = 187779241440. Its totient is φ = 107302423584.

The previous prime is 145305365323. The next prime is 145305365407. The reversal of 145305365335 is 533563503541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145305365335 - 213 = 145305357143 is a prime.

It is a super-2 number, since 2×1453053653352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145305365291 and 145305365300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1117733515 + ... + 1117733644.

It is an arithmetic number, because the mean of its divisors is an integer number (23472405180).

Almost surely, 2145305365335 is an apocalyptic number.

145305365335 is a deficient number, since it is larger than the sum of its proper divisors (42473876105).

145305365335 is a wasteful number, since it uses less digits than its factorization.

145305365335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2235467177.

The product of its (nonzero) digits is 1215000, while the sum is 43.

Adding to 145305365335 its reverse (533563503541), we get a palindrome (678868868876).

The spelling of 145305365335 in words is "one hundred forty-five billion, three hundred five million, three hundred sixty-five thousand, three hundred thirty-five".

Divisors: 1 5 13 65 2235467159 11177335795 29061073067 145305365335