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145310042435 = 5172100560583
BaseRepresentation
bin1000011101010100100…
…1110100100101000011
3111220001220110222120112
42013111021310211003
54340043332324220
6150430550301535
713332626660405
oct2072511644503
9456056428515
10145310042435
1156697804668
12241b40578ab
1310919a2663c
147066958b75
153ba6ebc5c5
hex21d5274943

145310042435 has 12 divisors (see below), whose sum is σ = 185232595728. Its totient is φ = 109409913216.

The previous prime is 145310042429. The next prime is 145310042443. The reversal of 145310042435 is 534240013541.

It is not a de Polignac number, because 145310042435 - 24 = 145310042419 is a prime.

It is a super-2 number, since 2×1453100424352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 50278847 + ... + 50281736.

It is an arithmetic number, because the mean of its divisors is an integer number (15436049644).

Almost surely, 2145310042435 is an apocalyptic number.

145310042435 is a deficient number, since it is larger than the sum of its proper divisors (39922553293).

145310042435 is a wasteful number, since it uses less digits than its factorization.

145310042435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100560622 (or 100560605 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 145310042435 its reverse (534240013541), we get a palindrome (679550055976).

The spelling of 145310042435 in words is "one hundred forty-five billion, three hundred ten million, forty-two thousand, four hundred thirty-five".

Divisors: 1 5 17 85 289 1445 100560583 502802915 1709529911 8547649555 29062008487 145310042435